Mathematics: Find the mean of the data in the dot plot below pls help

We will use substitution for the partial integration:The integral becomes:=2nd integration: we will add and subtract x^2 to the numerator:u-substitution:...=Finally:...=...

Find the mean of the data in the dot plot below

Ответ:

nikkiwoodward1ovgszp

18.03.2022

Mathematics

Step-by-step explanation:

The dot plot indicate that the fish caught during the trip were as follows;

1st attempt0

2nd attempt 3

3rd attempt 6

Total number of fish caught = 6+3+0 =9

Mean of the data = 9/3 = 3

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Ответ:

gracemerci1

18.03.2022

Mathematics

Hope this helps you

Step-by-step explanation:

means of data :- 9/3 = 3

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Ответ:

humpty21

09.07.2020

Mathematics

We will use substitution for the partial integration: $u=arc tan ( \frac{1}{x}), dv = dx \\ du= \frac{-dx}{(1+ x^{2}) x^{2} } , v=x$
The integral becomes:= $x arc tan x- \int {x \frac{-dx}{(1+ x^{2}) x^{2} } } \, dx = \\ =x arc tan x+ \int { \frac{dx}{(1+ x^{2} )x} } \, dx$
2nd integration:
we will add and subtract x^2 to the numerator: $\int { \frac{1+ x^{2} - x^{2} }{(1+ x^{2} )x} } \, dx= \\ \int { \frac{1}{x} } \, dx- \int { \frac{x}{1+ x^{2} } } \, dx = \\ ln(x) - \int { \frac{x}{1+ x^{2} } } \, dx$
u-substitution: $u=1+ x^{2} , du=2xdx, xdx= \frac{du}{2}$
...= $ln(x)- \frac{1}{2} \int { \frac{1}{u} } \, du=ln(x)- \frac{1}{2} ln(u)= \\ ln(x)-ln( \sqrt{1+ x^{2} )} =ln \frac{x}{ \sqrt{1+ x^{2} } }$
Finally:...= $xarctan( \frac{1}{x})+ln( \frac{x}{ \sqrt{1+ x^{2} } })+C$

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Find the mean of the data in the dot plot below pls help

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