brae72
21.09.2019 •
Mathematics
Find the minimum point for the function f(x) = |2x - 1| (0, ½) (½, 0) (0, -½) (-½, 0)
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Ответ:
0 = |2x - 1|
2x - 1 = 0
2x = 1
x = 1/2
Minimum point is (1/2, 0)
Ответ:
ZC = 85
AC = 158
Step-by-step explanation:
Z is the circumcenter of the triangle, so AZ, CZ, and BZ are all radii of the circle, hence congruent. ZC = 85.
ZF bisects AC, so AC is twice the length of FC, hence 2×79 = 158. AC = 158.