friendsalwaysbae
20.07.2019 •
Mathematics
Find the missing numerators in each of the following problems. a. 10⁄15 = ⁄60 b. ⁄108 = 4⁄9 c. 7⁄11 = ⁄121 d. ⁄144 = 2⁄6
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Ответ:
For 10/15 = x / 60
x = (10/15) * (60)
x = 40
For x / 108 = 4/9
x = (4/9) * (108)
x = 48
For 7/11 = x / 121
x = (7/11) * (121)
x = 77
For x / 144 = 2/6
x = (2/6) * (144)
x = 48
Ответ:
3.5
Step-by-step explanation:
Whenever you do 2.25 x 4 you get 9, then you add 7.50 and get 16.5. Afterwards, you subtract 3.5 from 20 leaving you with $3.5 dollars.