Find the particular solution to y " = sin(x) given the general solution y = -sin(x) + ax + b and the initial conditions y(pi/2) = 0 and y'(pi/2) = -2

-sin(x) + 1 + π

-sin(x) - 2x + π

-sin(x) - 2x - π

-sin(x) - 2x + π + 1

what grade are you in because this is tricky stuff

Beta is 60 degrees, and the angle of A should be 30 degrees.

Step-by-step explanation:

Its a right triangle, so it equals 180 degrees, there's a perpendicular angle at 'C' so its 90 degrees, B and its angle of 'Beta' 60 degrees, and angle 'A' can be 30 degrees. if in need of more explanation please look into complimentary and supplementary angles should give you a good idea.