aambitiouss
15.07.2019 •
Mathematics
Find the perimeter of a rhombus the length of whose diagonals are 10 cm and 24 m.
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Ответ:
check the picture below.
recall that in a rhombus, both diagonals bisect each other, namely cut each other in equal halves and at right-angles, so we end up with 4 right-triangles.
now, the sides in a rhombus are all equal, thus the perimeter is 13+13+13+13.
Ответ:
Spencer: 6x - 2 = -4x + 2 /+4x6x - 2 + 4x = -4x + 2 + 4x10x - 2 = 2
Jeremiah:6x - 2 = -4x + 2 /-6x6x - 2 - 6x = -4x + 2 - 6x-2 = -10x + 2
They both are correct. But in Jeremiah's version of solving the equation, we would have to multiply equation by -1, which we don't have to do in the Spencer's version.
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