Mathematics: Find the perimeter of the parallelogram with these vertices. , 47 , , −31 , , 41 , , −3−5 give an exact answer (not a decimal approximation). simplify your answer as much as possible.

Find the perimeter of the parallelogram with these

dedrick31

12.03.2022

The perimeter of the parallelogram is $2\sqrt{85}+12$

Explanation

According to the diagram below, Vertices of the parallelogram ABCD are: A (-3, 1) , B (4, 7) , C (4, 1) and D (-3, -5)

Using distance formula.....

Length of AB $= \sqrt{(-3-4)^2+(1-7)^2}=\sqrt{(-7)^2+(-6)^2}= \sqrt{49+36}=\sqrt{85}$

Length of BC $=\sqrt{(4-4)^2+(7-1)^2}=\sqrt{0+6^2}=\sqrt{36}=6$

As the opposite sides are equal in any parallelogram, so $CD=AB=\sqrt{85}$ and AD=BC= 6

Thus the perimeter $=2(\sqrt{85} +6)= 2\sqrt{85}+12$

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torichance6472

24.07.2021

1894076

Step-by-step explanation:

1953125-59049=1894076

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