Find the positive value of k such that the area of the region enclosed between the graph y=kcosx and the graph y=kx^2 is 2

Both these graphs will pass through the origin so you need to work out  the difference in areas by  integrating

INtegral k cos x (between the limits 0 and a) - Intgral kx^2 ( between 0 and a) = 2
Find k 
(where a is the value of x on positive side of the graph where the 2 curves intersect)

1)You multiply the number by 7.
3)0 to 9-add 9. 2 to 5-add 3. 4 to 1-subtract 3. 6 to -3- subtract 9. (Basically it's either add or subtract a number)
5)dunno, sry