ballin3294
16.10.2020 •
Mathematics
Find the range of the function integral from -4 to x of sqrt(16-t^2) dt.
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Ответ:
I believe it is 24
Step-by-step explanation:
Pythagorean theorem: a^2+b^2=c^2
We know A and C
7^2+b^2=25^2
Now we need to solve for B
We know that A+B will equal C
So C-A=B
25^2-7^2=576
Now we have to find the square root of 576 which is 24