Mathematics: Find the roots of the equation below. x2 - 6x + 12 = 0 -3 ± √3 3 ± √3 -3 ± i√3 3 ± i√3

C) Step-by-step explanation:6^2 + 3^2 = 45, and the is roughly 6.7 also equals roughly 6.7, so is the answer...

Find the roots of the equation below. x2 - 6x + - id261211340139, andybiersack154

Ответ:

rockabillyEli689

23.03.2021

Mathematics

$\displaystyle x = 3 \pm i\sqrt{3}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

BracketsParenthesisExponentsMultiplicationDivisionAdditionSubtractionLeft to Right

Algebra I

FactoringStandard Form: ax² + bx + c = 0Quadratic Formula: $\displaystyle x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

Algebra II

Imaginary Numbers: √-1 = i

Step-by-step explanation:

Step 1: Define

x² - 6x + 12 = 0

Step 2: Identify Variables

Compare the quadratic to standard form.

x² - 6x + 12 = 0 ↔ ax² + bx + c = 0

a = 1, b = -6, c = 12

Step 3: Find Roots

Substitute in variables [Quadratic Formula]: $\displaystyle x=\frac{-(-6)\pm\sqrt{(-6)^2-4(1)(12)}}{2(1)}$ [Quadratic Formula] Simplify: $\displaystyle x=\frac{6\pm\sqrt{(-6)^2-4(1)(12)}}{2(1)}$ [Quadratic Formula] [√Radical] Evaluate exponents: $\displaystyle x=\frac{6\pm\sqrt{36-4(1)(12)}}{2(1)}$ [Quadratic Formula] [√Radical] Multiply: $\displaystyle x=\frac{6\pm\sqrt{36-48}}{2(1)}$ [Quadratic Formula] [√Radical] Subtract: $\displaystyle x=\frac{6\pm\sqrt{-12}}{2(1)}$ [Quadratic Formula] [√Radical] Factor: $\displaystyle x=\frac{6\pm \sqrt{-1} \cdot \sqrt{12}}{2(1)}$ [Quadratic Formula] [√Radicals] Simplify: $\displaystyle x=\frac{6 \pm 2i\sqrt{3}}{2(1)}$ [Quadratic Formula] [Fraction - Denominator] Multiply: $\displaystyle x=\frac{6 \pm 2i\sqrt{3}}{2}$ [Quadratic Formula] [Fraction - Numerator] Factor: $\displaystyle x=\frac{2(3 \pm i\sqrt{3})}{2}$ [Quadratic Formula] [Fraction] Divide: $\displaystyle x = 3 \pm i\sqrt{3}$

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Find the roots of the equation below. x2 - 6x + 12 = 0

-3 ± √3
3 ± √3
-3 ± i√3
3 ± i√3

Ответ:

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