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26.01.2020 •
Mathematics
find the solutions of each equation on the interval [0,2pi).
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picture below.
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Ответ:
x = 0
Step-by-step explanation:
The argument x+3π/2 shifts the sine function 3π/2 to the left, making it equivalent to -cos(x). Then the equation becomes ...
-2cos(x) = -2
cos(x) = 1
On the interval [0, 2π), cos(x) is only 1 at x=0.
Ответ:
I am on the mission!
And yes dont cry but can you re upload the picture just as the person said?
:D