Mathematics: Find the sum of the first 41 terms of the following series, to the nearest integer. 12, 19, 26, ...

Step-by-step explanation:the answer is on quizlet...

Find the sum of the first 41 terms of the following

williamabigan

25.04.2021

The sum of the first 41 terms is 6232

Step-by-step explanation:

The sequence is an arithmetic progression with:

a = 12 -- first term

d = 7 --- common difference (this is calculated by 19 - 12 or 26 -19)

Required

The sum of the first 41 terms

This is calculated as:

$S_n = \frac{n}{2}(2a + (n-1)*d)$

In this case: n = 41

So:

$S_{41} = \frac{41}{2}(2*12 + (41-1)*7)$

$S_{41}= \frac{41}{2}*304$

$S_{41} = 6232$

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