Find the sum of the geometric sequence. 1 divided by 3, 2 divided by 3, 4 divided by 3, 8 divided by 3, 16 divided by 3

0.8418

Step-by-step explanation:

We have p = 0.36

Sample size = 200

We have to find the standard error of proportion

= √p(1-p)/n

= √0.36(1-0.36)/200

= 0.034

P(0.30<p^0.40)

= 0.30-0.36/0.034 = -1.76,

0.40-0.36/0.034 = 1.18

P(-1.76<z<1.18)

When we go to the standard normal distribution table

P(z<1.18) = 0.8810

P(z<-1.76) = 0.0392

0.8810 - 0.0392

= 0.8418

This is the probability of the sample proportion being between 0.30 and 0.40