Mathematics: Find the sum. Please

Find the sum. Please - id7023503, cicilee49

Ответ:

keripressley148

29.01.2022

Mathematics

$\dfrac{2y^2 +12y -8}{y^3-3y+2}$

Step-by-step explanation:

It usually works to factor the denominators, so you can determine the least common denominator.

$\dfrac{2y}{y^2-2y+1}+\dfrac{8}{y^2+y-2}=\dfrac{2y}{(y-1)^2}+\dfrac{8}{(y-1)(y+2)}\\\\=\dfrac{2y(y+2)}{(y-1)^2(y+2)}+\dfrac{8(y-1)}{(y-1)^2(y+2)}=\dfrac{2y^2+4y+8y-8}{(y-1)^2(y+2)}\\\\=\boxed{\dfrac{2y^2 +12y -8}{y^3-3y+2}}$

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Ответ:

7thaohstudent

13.08.2022

Mathematics

Step-by-step explanation:

15y = 3y - 15

15y - 3y = -15

12y = -15

$y = \frac{-15}{12}$

y = -1.25

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Find the sum. Please

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