Find the surface area of a pyramid with a square base with dimensions 100 mm by 100 mm and height of 75 mm.

To solve for the surface area of the pyramid, we make use of the formula:

A= l w + l [sqrt ((w / 2)^2 + h^2)] + w [sqrt ((l / 2)^2 + h^2))

where,

l and w are the base of the pyramid = 100 mm

h is the height of the pyramid = 75 mm

Substituting the given values into the equation:

A= 100 * 100 + 100 [sqrt ((100 / 2)^2 + 75^2)] + 100 [sqrt ((100 / 2)^2 + 75^2))

A = 10,000 + 100 (sqrt 2575) + 100 (sqrt 2575)

A = 20,148.90 mm^2

Therefore the surface area of the pyramid is about 20,149 mm^2.

When dividing fractions, you must have the fractions in a/b form, you must flip the second fraction, then you must change the division sign to multiplication.

To solve the first problem, 1/2 ÷ 3/4, here are the steps:

Step 1: Make sure both fractions are in a/b form, in this case they are

Step 2: Flip the second fraction: so basically we're turning 3/4 into 4/3

Step 3: Change the division sign to multiplication

Step 4: Solve

1/2 • 4/3 = 4/6 = 2/3

To solve the second problem, follow these steps

Step 1: Make sure both fractions are in a/b form, we need to turn 1 1/3 into the improper fraction 4/3. The second fraction does not need to be changed because it is already in a/b form

Step 2: Multiply Across:

4/3 • 3/4 = 12/12 = 1

Step-by-step explanation:

I hope this helps!