Find the surface area of the pyramid shown to
the nearest whole number.

a. 889 m
b. 1828 m
c. 914 m
d. 540 m

914 m^2 to the nearest whole number.

Step-by-step explanation:

The area of the hexagonal base is made up of 6 congruent triangles so its area = 6 *  1/2 base * height

= 6 * 1/2 * 12 * 6√3

= 216√3 m^2.

The area of each slanting triangle = 6 * 15 m^2 so the lateral area of the pyramid

= 6*6*15 = 540 m^2

Total surface area = 540 + 216√3

= 914.12 m^2.

The correct answer option is 82°.

Step-by-step explanation:

We can see from the given diagram that the quadrilateral ABCD is inscribed in a circle.

Now using the property:

'Opposite angles in any quadrilateral inscribed in a circle are supplements of each other'. Which means that their measures add up to a total of 180 degrees.

Thus, ∠A + ∠C = 180°.

If ∠A = 100°, then ∠C =  180° - 98°.

Therefore, ∠C =  82°.