Find the value of sec (θ)for an angle θ in standard position with a terminal Ray that passes through the point (4, -3)

B

Step-by-step explanation:

See the attachment.

We know that since the point is (4, -3), it's in the fourth quadrant. Drop a perpendicular from the point to the x-axis and produce a right triangle. This triangle has opposite as length -3 and adjacent as 4. We need to find the hypotenuse, so use the Pythagorean Theorem:

c² = a² + b²

c² = (-3)² + 4² = 9 + 16 = 25

c = 5

Secant is hypotenuse over adjacent, so we have:

sec(θ) = 5/4

The answer is B.

b

Step-by-step explanation:

Please see attached picture for full solution.