Find the value of the phasors v1 and v2 from the equations below (you can check your answers by plugging back into the original equations). express in phasor and sinusoidal form. plot the real components of v1 and v2 vs. time for an angular frequency of 1 hz. " + $ = 3∠60°, " − $ = 1∠90°

b = 3 and a = -1

Step-by-step explanation:

You have your given equation:

2a - 3b = -11

a + 3b = 8

You need to find what a and b is.

To find b:

2a - 3b = -11

-2a - 6b = -16

I multiplied a + 3b = 8 by -2. When you multiply a number you have to multiply all of them. You have to choose a number that would cancel out all of a.

So now your equation would look like this when you solve for b:

2a - 3b = -11

-2a - 6b = -16

a - 9 = -27 then you divide -9 to -27 which is 3 so b = 3.

To find a:

2a - 3b = -11

a + 3b = 8

I multiplied a + 3b = 8 by -1 and 2a - 3b = -11 by -1 as well.

Your equation will look like this when you solve for a:

-2a + 3b = 11

-1a - 3b = -8

-3a = 3 then divide -3 to 3 which is -1 so a = -1.

Check to see if you have the correct answer by plugging in the number you got for a and b into the equation and solve.

1. 2(-1) -3(3) = -11

 -2 - 9 = -11

2. -1 + 3(3) = 8

   -1 + 9 = 8