Find the volume in terms of pi of a sphere with a surface area of 9 pi square feet

So we want to know the volume of a sphere in terms of pi if we know the area of the sphere is equal to A=9pi. So the area of the sphere is A=4*pi*r^2 and the volume V=(4/3)*pi*r^3. We can get the radius from the area: 9pi=4*pi*r^2 and we see the pi cancels out: 9=4*r^2. We divide by 4 and take the square root: r=sqrt(9/4)=3/2. So r=3/2 and we can input it into volume V.

V=(4/3)*(3/2)^3*pi=(4/3)*(27/8)*pi=(9/4)*pi. 

So the volume of the sphere is V=(9/4)*pi cubic feet.

we know that

The measure of the angle formed by chords that intersect inside the circle is the sum of the chords' intercepted arcs. (Angles of intersecting chords theorem)

so

in this problem

therefore

the answer is

The measure of the arc TU is equal to