he0gaubong
13.10.2019 •
Mathematics
Find the volume of a frustum of a right pyramid whose lower base is a square with a side 5 in. and whose upper base is a square with a side 3in and whose altitude is 12in
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Ответ:
a1=100sa.inch
a2=25 sq.inch and
h=12inch
so the volume =(1/3)(12)[100+25+√(100*25)]
=4*[125+50]
=4*175=700 cubic inches or [inch cubed]
Ответ:
x = 36/5 = 7.2
volume of frustum = 1/3 * 5^2 * 12 - 1/3 * 3^2 * 7.2
= 100-21.6
= 78.4 in^3
Ответ:
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