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21.08.2019 •
Mathematics
Find the x and y intercepts of the quadratic equation
f(x)=-x^2+4x-4
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Ответ:
f(x) = -x² + 4x - 4
0 = -x² + 4x - 4
x = -(4) +/- √((4)² - 4(-1)(-4))
2(-1)
x = -4 +/- √(16 - 16)
-2
x = -4 +/- √(0)
-2
x = -4 +/- 0
-2
x = -4 + 0 x = -4 - 0
-2 -2
x = -4 x = -4
-2 -2
x = 2 x = 2
The solution to the problem is {2, 2}, or {2}. The x - intercept of the problem is (2, 0).
Y - Intercept
f(x) = -x² + 4x - 4
f(x) = -(0)² + 4(0) - 4
f(x) = -(0) + 0 - 4
f(x) = -0 + 0 - 4
f(x) = 0 - 4
f(x) = -4
The y - intercept of the problem is (0, -4).
Ответ:
no
Step-by-step explanation:
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