Find three consecutive even integers if three times the first integer is two times the third

Step-by-step explanation:

Smallest Integer = 2x - 2

Middle integer = 2x

Largest integer = 2x + 2

All three are every

3(2x - 2) = 2(2x + 2)

6x - 6 = 4x + 4                Add 6 to both sides

6x = 4x + 6 + 4               Combine

6x = 4x + 10                    Subtract 4x from both sides

6x-4x = 10                      Combine

2x = 10                           Divide by 2

x = 10/2

x = 5

3*8 = 2*12

24 = 24

So the answers are correct.