Chen19241
01.09.2019 •
Mathematics
Find three consecutive even integers such that the sum of the smallest integer and twice the second is 12 more than the third (only an algebraic solution will be accepted )
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Ответ:
X + 2( x + 1) = 12 + x + 2
X + 2x + 2 = 12 +x + 2
3x + 2 = x + 14
3x + 2-2 = x + 14 -2
3x = x +12
3x – x = x – x + 12
2x = 12
2x/2 = 12/2
X = 6
Plug 6 into the formula to check
6 + 2( 6 + 1) = 12 + 6 + 2
6 + 12 + 2 = 12 + 6 + 2
20 = 20
The numbers are: 20, 21, 22
Ответ:
answer: the correct option is, (a) half
step-by-step explanation:
inscribed angle theorem : it is defined as the measure of an inscribed angle in a circle is half of the measure of the intercepted arc.
in a given circle the
for example :
if then the
the image is shown below.