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struckedblazing
09.07.2019 •
Mathematics
Find three consecutive integers such that the product of the two largest is 20 more than the square of the smallest number
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Ответ:
Givens
the smallest integer is x
The second smallest integer is x + 1
The largest integer is x + 2
Equations
(x + 1)(x + 2) = x² + 20
Solution
x² + x + 2x + 2 = x² + 20 Subtract x² from both sides
3x + 2 = 20 Subtract 2 from both sides.
3x = 20 - 2
3x = 18 Divide by 3
x = 18/3
x = 6
The three numbers are 6,7 and 8
Check
7*8 = 6^2 + 20
56 = 36 + 20
56 = 56
The equation's solution does check.
Ответ:
Here, we have to examine the equation of the straight line which is denoted by: y = m x +c where "m" is the slope which represents the steepness and c is the y-intercept
Here, the two linear functions have the same slope "m" and the same y-intercept "c". When both these are the same, the two linear functions are representing the same straight line.
Therefore, Jeremy is correct in his argument.