Find three consecutive multiples of 4 so that the product of the first and second number is 16 more than 5 times the third number

Multiplues of 4 are 4n where n is a natural number

they numbers are 4n,4(n+1), 4(n+2)

(4n)(4(n+1))=16+5(4(n+2))
expand
16n²+16n=16+20n+40
16n²+16n=56+20n
divide both sides by 4
4n²+4n=14+5n
minus 14+5n both sides
4n²-n-14=0
factor
(n-2)(4n+7)=0
set to zero
n-2=0
n=2

4n+7=0
4n=-7
n=-7/4, false, n has to be a natural number

n=2

so
4n=8
4(n+1)=12
4(n+2)=16

the numbers are 8,12,16

w=4

Step-by-step explanation:

-11=8w-43

32=8w

w=4