Find two consecutive ODD integers such that: The square of the larger is 120 more than the square of the smaller

See explanation

Step-by-step explanation:

Le the number be x and x+2

The information given can be formed into and equation as:

(x + 2)² = x² + 120

(x + 2)(x + 2) = x² + 120

x² + 2x + 2x + 4 = x² + 120

Collect like terms

x² - x² + 2x + 2x = 120 - 4

4x = 116

x = 116/4

x = 29

The smallest number is 29

The larger number is x + 2 = 29 + 2 = 31