christylivingsowzxa2
05.02.2020 •
Mathematics
Find two positive numbers whose sum is 100 and the sum of whose squares is a minimum.
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Ответ:
Sum of its squares is given by S = x^2 + (100 - x)^2
For the sum of the squares to be minimum, dS/dx = 0
dS/dx = 2x - 2(100 - x) = 0
2x - 200 + 2x = 0
4x = 200
x = 50.
The two numbers is 50 and 50.
Ответ:
Ok You're probably here from K12 so heres the
Conclusion: If a polygon undergoes a rigid transformation, then the image and pre-image have equal perimeters.
I just took the test and got this right, I'm a K12 student as well.
Hope this helps :)