Mathematics: Find zeros from vertex form y=4(x-2)^2

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Find zeros from vertex form y=4(x-2)^2 - id4225505838, marisol56

Ответ:

neonbluefaith

21.01.2022

Mathematics

Explanation:

The vertex form of the equation of a parabola is given by the form:

$y=a(x-h)^2+k \\ \\ \\ Where: \\ \\ a \ \text{is the leading coefficient and (h,k) the vertex of the parabola:}$

The zeroes are the x-values that touches the x-axis, that is, those x-values at which y=0 . Form the equation it's easy to know that at x=2 the output y=0 because:

$y=4(x-2)^2 \\ \\ If \ x=2: \\ \\ y=4(2-2)^2 \\ \\ y=4(0)^2 \\ \\ y=0$

So the only zero occurs at x=2

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Find zeros from vertex form y=4(x-2)^2

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