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sailesd57
28.01.2020 •
Mathematics
Finding ]
find the perimeter and area of each
1)
| 10
10
2
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Ответ:
Number of panels produced by Plant B is 8,000.
Step-by-step explanation:
The number of panels produced by Plant A = 16,000
The number of defective panels from A = 5%
Now, 5% of 16,000 =![\frac{5}{100} \times 16,000 = 800](/tpl/images/0399/7578/faca6.png)
So, out of 16,000 panels produced by pant A , 800 are defective. .. (1)
Let us assume number of panels produced by Plant B = m
The number of defective panels from B = 2%
Now, 2% of m =![\frac{2}{100} \times m = 0.02 m](/tpl/images/0399/7578/d5fd4.png)
So, out of total m panels produced by pant B , 0.02 m are defective. .. (2)
Now, total panels produced over all = Panels by A + Panels by B
= 16,000 + m
The percentage of defected panels over all = 4%
Now, 4% of (16,000 + m) =![\frac{4}{100} \times (16,000+m) = (0.04)(16,000 + m)](/tpl/images/0399/7578/11b15.png)
Also, the total number of defective panels = Defective from A + Defective from B
⇒(0.04)(16,000 + m) = 800 + 0.02 m from (1) and (2)
or, 640 + 0.04 m = 800 + 0.02
or, 0.02 m = 160
⇒ m = 160 /0.02 = 8,000
or, m = 8,000
Hence, Number of panels produced by Plant B is 8,000.