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landenDfisher

24.09.2021

Mathematics

$(9x+2)(4x^2+35x-9)=0\\\\
9x+2=0\\
9x=-2\\
x=-\frac29\\
\\
4x^2+35x-9=0\\
\Delta=1225+144=1369\ \ \sqrt{\Delta}=37\\
x_1=\frac{-35-37}{2 \cdot 4}=-9\\
\\
x_2=\frac{-35+37}{2\cdot 4}=\frac14\\
\\
x\in\{-9,-\frac29,\frac14\}$

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