Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is the solution set of this problem? (negative infinity, negative 21) (negative infinity, negative 21 right-bracket Left-bracket negative 21, positive infinity) (21, positive infinity)

b. (- infinity, - 21]

Step-by-step explanation:

Let x be the unknown number. Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26.

5 × (x + 27) ≥ 6 × (x + 26)

We apply the distributive property.

5x + 135 ≥ 6x + 156

135 - 156 ≥ 6x - 5x

-21 ≥ x

x is less than or equal to -21. The solution set of this problem is

(- infinity, - 21].

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Step-by-step explanation:

Given:

Fraction of students that are in fourth grade =

In order to reduce this fraction in to simplest form, we need to find the highest common factor for both the numerator and denominator and divide each of the numerator and denominator by the highest common factor (HCF)

The numerator is 4 and the denominator is 24.

Factors of 4 = 1, 2, 4

Factors of 24 = 1, 2, 3, 4, 6, 8, 12, 24

As seen from the above, the highest common factor for 4 and 24 is 4.

So, we divide both numerator and denominator by the highest common factor which is 4. This gives,

Therefore, the fraction of students that are in fourth grade in simplest form is .