For a certain animal, suppose that the number of babies born is independent for each pregnancy. this animal has a 70% chance of having one baby and a 30% chance of having 2 babies at each pregnancy. let X be a random variable that represents the total number of babies if the animal gets pregnant twice. construct a table showing the probability distribution of X.

- - 2z - 5

Step-by-step explanation:

This is the equation that you started off with:

(x - z - )(x + z + )

You can't really use FOIL on this because that's used in multiplying binomials, and this is a trinomial, but you can still break it up and simplify it this way:

(a + b + c)*(d + e + f) = (a(d + e +f)) + (b(d + e + f)) + (c(d + e + f))

So, applying that idea to the actual equation:

x(x + z + ) -z(x + z + ) - (x + z + )

= x^2 + xz + x -xz -z^2 - z - x - z - 5

= x^2 - z^2 - 2z - 5

or