For all functions of the form f(x) = ax2 + bx + c, which is true when b = 0?

the graph will always have zero x-intercepts.
the function will always have a minimum.
the y-intercept will always be the vertex.
the axis of symmetry will always be positive.

The correct answer for this question is "The y-intercept will always be the vertex." For all the functions of the form f(x) = ax^2 + bx + c, which is a quadratic function, the statement that is true when the value of b is zero is that the y-intercept will always be the vertex of the graph.

The y-intercept will always be the vertex

Step-by-step explanation:

The correct answer for this question is "The y-intercept will always be the vertex." For all the functions of the form f(x) = ax^2 + bx + c, which is a quadratic function, the statement that is true when the value of b is zero is that the y-intercept will always be the vertex of the graph.

Count the rise and run to find the slope, 1. Next, find the y-intercept-(-1). Now make the slope-intercept equation-  y = 1x - 1. Double check, put x = 2 in the equation-  y = 1(2) - 1 (=) y = 2 - 1 (=) y = 1.

So, the slope-intercept equation for this line is y = 1x - 1.