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emmalado45
31.01.2020 •
Mathematics
For each item find how many times greater the 2011 cost is than 1955 cost.round your answer to the nearest hundredth.
1955 2011
movie adddmision\ $0.75 \$9.50
regular popcorn \$0.25 \4.25
drink \$0.35 \$2.75
movie addmision regularpopcorn drink
pl now
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Ответ:
Movie admission:
In 1955 the price was $0.75 and in 2011 the price was $9.50
then we must solve $9.50/$0.75 = 12.67
where I already rounded it to the nearest hundredth.
Then, in 2011 the price was 12.67 times bigger than the one in 1955.
Regular popcorn:
In 1955 the price was $0.25 and in 2011 the price was $4.25
then: $4.25/$0.25 = 17
The price in 2011 was 17 bigger than in 1955
Drink:
in 1955 the price was $0.35 and in 2011 the price was $2.75
then: $2.75/$0.35 = 7.86
The price in 2011 was 7.86 times bigger than in 1955.
Ответ:
Its written as
Hope this helps you