Mathematics: For i^2 = -1, (3 + 2i )(5- 4i ) = ? plz i begz u

FalseStep-by-step explanation:From the question we are told that The coefficient for the training is The standard error is The confidence level is 95% Generally the level of significant is mathematically represented as = Generally the critical value of obtained from the normal distribution table is Generally the test statistics is mathematically represented as = = Generally given that the Hence there is no sufficient evidence to conclude that the program has a positive and statistically significant...

For i^2 = -1, (3 + 2i )(5- 4i ) = ? plz i begz - id2132544375777, lexibyrd120

Ответ:

rosezgomez97

05.12.2022

Mathematics

False

Step-by-step explanation:

From the question we are told that

The coefficient for the training is r = 0.55

The standard error is SE = 1.06

The confidence level is 95%

Generally the level of significant is mathematically represented as

$\alpha =( 100 -95)\%$

=> $\alpha = 0.05$

Generally the critical value of $\alpha = 0.05$ obtained from the normal distribution table is $Z_{0.05} = 1.645$

Generally the test statistics is mathematically represented as

$t = \frac{r }{SE}$

=> $t = \frac{0.55}{1.06}$

=> t = 0.5189

Generally given that the $t < Z_{\alpha }$

Hence there is no sufficient evidence to conclude that the program has a positive and statistically significant impact on wages at a 95% confidence level.

So the answer is False

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For i^2 = -1, (3 + 2i )(5- 4i ) = ?
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