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bekzod37

23.09.2020

Mathematics

Interval=4.85±0.33

Interval (5.18,4.52)

Step-by-step explanation:

Consider the formula for the interval:

interval=± $\frac{Z*S}{\sqrt{n} }$

Where:

X is the mean value

S is the standard deviation

n is the sample size

Z is the distribution

Alpha=1-0.95=0.05

$Z_{alpha/2}=Z_{0.05/2} =Z_{0.025}$ =1.96 (From Standard Z-Distribution Table)

Now use the above formula

interval= 4.85 ± $\frac{1.96*0.79}{\sqrt{22} }$

Interval=4.85±0.33

Interval (5.18,4.52)

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