For questions 1 - 8, calculate the surface area. If necessary, round to the nearest
hundredth

Vol sq. pyramid = 1/3×s^2×h
Vol cube = s^3
since height of cube is 4, that height = s
V = (4)^3 = 64 cubic cm
now since their Vs are the same,
1/3×s^2×h = 64
they said length of side in square pyramid
was 2, then:
1/3×(2)^2×h = 64
1/3×4×h = 64
4/3 h = 64
h = 64×3/4 = 16×3 = 48 cm

D) is the correct answer