Bryanguzman2004
28.02.2020 •
Mathematics
For the accompanying data set, draw a scatter diagram of the data.x 2 6 6 7 9y 3 2 6 9 5B. by hand compute the correlation coefficient. r = (round to three decimals as needed.)C. Fill in the blanks: Because the correlation coefficient is (positive or negative) and the absolute value of the correlation coefficient, , is (greater or not greater) than the critical value for this data set,___, (no, a positive, or a negative) linear relation exists between x and y. (round to three decimal places as needed.)Critical values for the correlation coefficient tablen 3 0.9974 0.9505 0.8786 0.8117 0.7548 0.7079 0.66610 0.63211 0.60212 0.57613 0.55314 0.53215 0.51416 0.49717 0.48218 0.46819 0.45620 0.44421 0.43322 0.42323 0.41324 0.40425 0.39626 0.38827 0.38128 0.37429 0.36730 0.361
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Ответ:
Step-by-step explanation:
Hello!
a.
Given the data corresponding the variables:
x 2 6 6 7 9
y 3 2 6 9 5
The Scatterplot is attached.
b.
To compute the correlation coefficient you need several auxiliary calculations:
∑X= 30
∑X²= 206
∑Y= 25
∑Y²= 155
∑XY= 162
r= 0.429 ≅ 0.43
c.
The critical value for r has n-2 degrees of freedom, let's say for example you have α:0.05
For a two-tailed test.
Because the correlation coefficient is positive and the absolute value of the correlation coefficient, _0.43___, is not greater than the critical value for this data set,_0.878__, no linear relationship exists between x and y.
I hope it helps!
Ответ:
OMG, I REMEMBER TAKING THIS EXACT HOMEWORK. DO U GO TO FLVS OR TAMPA BAY BLVD :OO