For the following distribution: x P(x)
0 0.900
1 0.09
2 0.007
3 0.003
What is the variance of the distribution?
a. 1.13.
b. 1.5.
c. 0.113.
d. 2.1.

Step-by-step explanation:

Given, :

x P(x)

0 0.900

1 0.09

2 0.007

3 0.003

The expected variance ; Var(X) = x²*p(x) - E(X)²

The expected mean, E(X) = x*p(x)

E(X) = (0*0.9) + (1*0.09) + (2*0.007) + (2*0.003) = 0.113

Var(X) = [(0^2*0.9) + (1^2*0.09) + (2^2*0.007) + (3^2*0.003)] - 0.113^2

Var(X) = 0.145 - 0.012769

Var(X) = 0.132

I need this answer to

Step-by-step explanation:

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