thil54451
26.02.2021 •
Mathematics
For the function N(y) = 4|3y – 8– 4, evaluate N(y) + N(1).
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Ответ:
4|3y-8|+12
Step-by-step explanation:
N(1)=4|3(1)-8|-4
N(1)=16
Now we have:
N(y)+N(1)=4|3y-8|-4+16
N(y)+N(1)=4|3y-8|+12
Ответ: