For what positive real value of k, if any, is the determinant of the matrix {k/3 4/k} equal to k? (note: The determinant of matrix {a/c b/d) = ad-bc)

~options~
A. 3
B. 4
C. 12
D. (square root) 12
E. There is no value of K.

Step 1
find the equation of f(x)
points
(2,1)  and (0,-3)
m=(y2-y1)/(x2-x1)> m=(-3-1)/(0-2)> m=2
y-y1=m(x-x1)> y+3=2*(x-0)> y=2x-3
f(x)=2x-3

step 2
find the equation of g(x)
points 
(0,6)  and (2,-2)
m=(y2-y1)/(x2-x1)> m=(-2-6)/(2-0)> m=-4
y-y1=m(x-x1)> y-6=-4*(x-0)> y=-4x+6
g(x)=-4x+6

step 3
find the value of k
If g(x) = k* f(x)
so
-4x+6=k*[2x-3]> -4x+6=2kx-3k
-4x=2kx> k=-2
6=-3k> k=-2

the answer is 
k=-2