For what value of jn is mn parallel to kl

answer: we have from thales theorem that because the 2 triangles are similar, jm/jk=jn/jl. we have that jn=x, jl=x+24 and that jm=7 and jk=28. substituting, we get:

x/(x+24)=7/28.

hence, x/(x+24)=1/4. this leads to 4x=x+24, 3x=24, x=8. we have solved for x=jn and this is equal to 8.

step-by-step explanation: