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dakodahepps
21.05.2020 •
Mathematics
For what values of θ is sinθ < cosθ when 0 ≤ θ < π ?
Will mark brainliest and 50 points for first to answer!
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Ответ:
=========================================================
How to get this
Use the unit circle to note that
when
(aka 45 degrees)
Beyond this point, cosine is smaller than sine. This means that anything from 0 to pi/4 will have sine be smaller than cosine. It might help to graph y = sin(x) and y = cos(x) on the interval from x = 0 to x = pi.
The two curves y = sin(x) and y = cos(x) intersect at the point![\left(\frac{\pi}{4}, \frac{\sqrt{2}}{2}\right)](/tpl/images/0658/1049/93298.png)
-------------------------------
Here's a more detailed picture of whats going on.
Intersect the intervals
and
and you'll end up with the final answer ![0 \le \theta < \frac{\pi}{4}](/tpl/images/0658/1049/7b559.png)
Ответ:
x < -6
Step-by-step explanation:
-2x - 4 > 8
-2x > 12
x < -6, you have to flip the inequality when you multiply or divide by a negative