For what values of theta, 0°

9514 1404 393

  38.5°

Step-by-step explanation:

A triangle solver can give an answer easily. The angle is 38.5°.

__

The law of cosines can be written to solve for an unknown angle C opposite side 'c' and flanked by sides 'a' and 'b'.

  C = arccos((a² +b² -c²)/(2ab))

Here, we have a=35, b=48, c=30, so the angle is ...

  C = arccos((35² +48² -30²)/(2·35·48)) = arccos(2629/3360) ≈ 38.515°

The angle the cable makes with the pole is about 38.5°.