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Annabeans1105
12.01.2020 •
Mathematics
Four times a number increased by seven must be at least 31 but at most 55. which interva
represents the values of the number in this situation?
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Ответ:
6
x
8
Step-by-step explanation:
We'll represent the number with the expression 4x + 7
Then, we'll set up the inequality:
31
4x + 7
55
24
4x
48
6
x
8
Ответ:
x= -1
Step-by-step explanation:
3(4x+2)-4x-2= -4
12x+6-4x-2= -4
12x-4x+6-2= -4
8x+4= -4
8x= -4-4
8x= -8
x= -8÷8
x=-1