Fred needs 12 meters of ribbon to wrap each gift. He has a spool of ribbon that contains 18 feet of ribbon. One meter is equivalent to approximately 3 feet. How many gifts of same dimension can he wrap using the spool of ribbon

5

Step-by-step explanation:

The computation of the gits is shown below;

Given that

The ribbon which is used to wrap the gift = 1.2m

The ribbon that he spoiled = 18feet

based on the above information

As we know that 3feet = 1m

1foot = 1 ÷ 3 m

Now

18feet = 1 ×18 ÷ 3

18 feet = 6m

Now,

gift can be packed = 6 ÷ 1.2

= 60 ÷ 12

= 5

Solution given:

perpendicular [P]=80ft

base[B]=18ft

hypotenuse [H]=?

By using Pythagoras law

H²=P²+B²

H²=80²+18²

H=

the length of the hypotenuse in feet is 82ft.