Mathematics: FREE POINTS cuz its my waifu day

Step-by-step explanation:solving for dy/dxmultiply the equation out to remove parenthesesnow differentiating in terms of x ()isolating dy/dx to one side...

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CHRONICxDJ

07.01.2023

Mathematics

$\frac{dy}{dx} =\frac{4x^3+3x^2y-5y^2}{10xy-3y^2-x^3}$

Step-by-step explanation:

solving for dy/dx

multiply the equation out to remove parentheses

x^4 + x^3y = 5xy^2 -y^3

now differentiating in terms of x ( $\frac{dy}{dx}$ )

$4x^3 +3x^2y + x^3(\frac{dy}{dx} ) = 5y^2 + 10xy(\frac{dy}{dx} )-3y^2(\frac{dy}{dx} )$

isolating dy/dx to one side

$4x^3 +3x^2y - 5y^2= 10xy(\frac{dy}{dx} )-3y^2(\frac{dy}{dx} )-x^3(\frac{dy}{dx} )$

$4x^3 +3x^2y - 5y^2= \frac{dy}{dx}(10xy-3y^2-x^3)$

$\frac{dy}{dx} =\frac{4x^3+3x^2y-5y^2}{10xy-3y^2-x^3}$

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