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05.07.2019 •
Mathematics
From a shipment of 65 transistors, 6 of which are defective, a sample of 5 transistors is selected at random.
(a) in how many different ways can the sample be selected?
(b) how many samples contain exactly 3 defective transistors?
(c) how many samples do not contain any defective transistors?
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Ответ:
a) 8259888
b) 34220
c) 45057474
Step-by-step explanation:
Given,
The total number of transistor = 65,
In which, the defective transistor = 6,
So, the number of non defective transistor = 65 - 6 = 59,
Since, out of these transistor 5 are selected,
a) Thus, the number of ways = the total possible combination of 5 transistors =![{65}C_ 5](/tpl/images/0052/2540/8bac6.png)
b) The number of samples that contains exactly 3 defective transistors = the possible combination of exactly 3 defective transistors =![{6}C_3\times {59}C_2](/tpl/images/0052/2540/221a1.png)
c) The number of sample without any defective transistor = The possible combination of 0 defective transistor =![^6C_0\times ^{59}C_5](/tpl/images/0052/2540/1edd2.png)
Ответ:
Step-by-step explanation:
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