Mathematics: From the top of a 150 m high-rise building, two cars on the same road below the building are seen at an angle of depression of and on each side of the building. Find the distance between the two cars to the nearest meter.

no because theyre reallly delicate and the velocity they are going by would help at allStep-by-step explanation:...

From the top of a 150 m high-rise building, two

wrightlilybug07

23.01.2022

237m

Step-by-step explanation:

The question is incomplete.

Find attached the picture with the complete question including the diagram.

The second figure shows the construction of two right triangles with common height of 150m.

To find the distance between the two cars, you can calculate the horizontal leg of each right triangle.

1. For the triangle on the left side of the picture:

Naming x the horizontal leg:

$tan(60\º)=\dfrac{150m}{x}\\ \\ \\ x=\dfrac{150m}{tan(60\º)}\\ \\ \\ x=86.60m$

2. For the triangle on the right side of the picture:

Since it is a 45 - 45 - 90 triangle, the horizontal leg has the same lenght as the other leg, which is the height of the building: 150m

3. Distance between the two cars:

Add the lengths of the two legs: 86.60m + 150m = 236.60m.

Round to the nearest meter. That is 237m. ← answer

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