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gamer0078
29.10.2020 •
Mathematics
g If a snowball melts so that its surface area decreases at a rate of 8 cm 2/min, find the rate at which the diameter decreases when the diameter is 9 cm.
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Ответ:
Step-by-step explanation:
The snowball is spherical in nature
The total surface area of the ball = 4πr²
Or 4π(d/2)²
S = 4πd²/4
S = πd²
d is the diameter of the ball
The rate at which the area is decreasing is expressed as;
dS/dt = dS/dd • dd/dt
dd/dt is the rate at which the diameter is decreasing
dS/dd = 2πd
dS/dt = 2πd • dd/dt
dS/dt = 2π(9) • dd/dt
8 = 18π•dd/dt
dd/dt = 8/18π
dd/dt = 4/9(3.14)
dd/dt = 4/28.26
dd/dt = 0.1415cm/min
Hence the diameter is decreasing at the rate of 0.1415cm/min
Ответ: