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lestessanders02
08.01.2021 •
Mathematics
Gabe deposits $2,500 into each of two savings accounts.
Account ONE earns 4% annual simple interest.
Account TWO earns 4.5% interest compounded annually.
What is the sum of the balances of Accounts ONE and TWO at the end of 3 years?
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Ответ:
$5,612.16
Step-by-step explanation:
Part 1) Account I earns 4% annual simple interest.
we know that
The simple interest formula is equal to A = P (1+rt)
where
A is the Final Investment Value
P is the Principal amount of money to be invested
r is the rate of interest
t is Number of Time Periods
in this problem we have:
t = 3 years
P = $2,500
r = 4% = 4/100 = 0.04
substitute in the formula above
A = 2,500 (1 + 0.04 * 3)
A = 2,500 (1.12)
A = $2,800
Part 2) Account II earns 4% interest compounded annually.
we know that
The compound interest formula is equal to: A = P (1 + r/n)nt
where
A is the Final Investment Value
P is the Principal amount of money to be invested
r is the rate of interest in decimal
t is Number of Time Periods
n is the number of times interest is compounded per year
in this problem we have
t = 3 years
P = $2,500
r = 4% = 4/100 = 0.04
n = 1
substitute in the formula above
A = 2,500 * (1 + 0.04/1)3
A = 2,500 * (1.04)3
A = $2,812.16
Part 3) What is the sum of the balances of Account I and Account II at the end of 3 years?
Sum the two final investment:
$2,800 + $2,812.16 = $5,612.16
Ответ:
The reduced insurance cost is £685.42.
Step-by-step explanation:
The amount paid per year for insurance = £714.73
Now the price is reduced by 4.1%
Calculating 4.1% of the amount £ 714.73, we get:
4.1% of 714.73 =
⇒4.1% of £ 714.73 = £29.30
So, the reduced insurance amount = £ 714.73 - £29.30
= £685.42
Hence, the reduced insurance cost is £685.42.